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Free Grade 3 Compound Shapes in Context Common Errors Quizzes

Free Grade 3 quizzes for Compound Shapes in Context Common Errors: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Foundation

Estimated time

30 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain compound shapes in context common errors

    Explain compound shapes in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate compound shapes in context common errors

    Calculate compound shapes in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare compound shapes in context common errors

    Compare compound shapes in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify compound shapes in context common errors

    Justify compound shapes in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Compound Shapes in Context Common Errors works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 14 cm by 15 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 8 cm by 10 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 3 cm by 13 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 11 cm by 8 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 4 cm and height 9 cm. Find its area.[2]
  6. 6.A triangle has base 22 cm and height 4 cm. Find its area.[2]
  7. 7.A triangle has base 26 cm and height 5 cm. Find its area.[2]
  8. 8.A triangle has base 24 cm and height 11 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 6 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 12 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 2 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 58 cm, area 210 cm²

    Perimeter = 14 + 15 + 14 + 15 = 58 cm. Area = 14 × 15 = 210 cm².

  2. 2. Perimeter 36 cm, area 80 cm²

    Perimeter = 8 + 10 + 8 + 10 = 36 cm. Area = 8 × 10 = 80 cm².

  3. 3. Perimeter 32 cm, area 39 cm²

    Perimeter = 3 + 13 + 3 + 13 = 32 cm. Area = 3 × 13 = 39 cm².

  4. 4. Perimeter 38 cm, area 88 cm²

    Perimeter = 11 + 8 + 11 + 8 = 38 cm. Area = 11 × 8 = 88 cm².

  5. 5. 18 cm²

    Area = ½ × base × height. ½ × 4 × 9 = 18 cm².

  6. 6. 44 cm²

    Area = ½ × base × height. ½ × 22 × 4 = 44 cm².

  7. 7. 65 cm²

    Area = ½ × base × height. ½ × 26 × 5 = 65 cm².

  8. 8. 132 cm²

    Area = ½ × base × height. ½ × 24 × 11 = 132 cm².

  9. 9. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

  10. 10. Area 113.1 cm², circumference 37.7 cm

    Area = πr² = π × 6² = 113.1 cm². Circumference = 2πr = 2 × π × 6 = 37.7 cm.

  11. 11. Area 452.4 cm², circumference 75.4 cm

    Area = πr² = π × 12² = 452.4 cm². Circumference = 2πr = 2 × π × 12 = 75.4 cm.

  12. 12. Area 12.6 cm², circumference 12.6 cm

    Area = πr² = π × 2² = 12.6 cm². Circumference = 2πr = 2 × π × 2 = 12.6 cm.

Worked examples

Easy example

A rectangle is 15 cm by 12 cm. Find its perimeter and area.

  1. Perimeter = 15 + 12 + 15 + 12 = 54 cm.
  2. Area = 15 × 12 = 180 cm².
  3. Answer: Perimeter 54 cm, area 180 cm²
Medium example

A triangle has base 24 cm and height 2 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 24 × 2 = 24 cm².
  3. Answer: 24 cm²
Hard example

Find the area and circumference of a circle with radius 10 cm (to 1 d.p.).

  1. Area = πr² = π × 10² = 314.2 cm².
  2. Circumference = 2πr = 2 × π × 10 = 62.8 cm.
  3. Answer: Area 314.2 cm², circumference 62.8 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

OCR OCR-953.1 — Mapped statement covering Compound Shapes in Context Common Errors.CAMBRIDGE CAM-343.2 — Mapped statement covering Compound Shapes in Context Common Errors.

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Frequently asked

Is this Grade 3 Compound Shapes in Context Common Errors quiz really free?
Yes. Every quizzes on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Compound Shapes in Context Word Problems, Compound Shapes in Context Techniques, Working with Compound Shapes. Each one has its own free lesson, worksheet and quiz.
How is the quiz sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Compound Shapes in Context Common Errors?
Move on to Introducing Compound Shapes, Working with Compound Shapes, which build directly on this idea.

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