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Free Grade 3 Compound Shapes Flashcards

Free Grade 3 flashcards for Compound Shapes: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Foundation

Estimated time

20 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain compound shapes

    Explain compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate compound shapes

    Calculate compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare compound shapes

    Compare compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify compound shapes

    Justify compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Compound Shapes works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 7 cm by 13 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 9 cm by 15 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 13 cm by 7 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 15 cm by 11 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 22 cm and height 3 cm. Find its area.[2]
  6. 6.A triangle has base 12 cm and height 12 cm. Find its area.[2]
  7. 7.A triangle has base 12 cm and height 13 cm. Find its area.[2]
  8. 8.A triangle has base 28 cm and height 11 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 8 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 12 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 6 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 40 cm, area 91 cm²

    Perimeter = 7 + 13 + 7 + 13 = 40 cm. Area = 7 × 13 = 91 cm².

  2. 2. Perimeter 48 cm, area 135 cm²

    Perimeter = 9 + 15 + 9 + 15 = 48 cm. Area = 9 × 15 = 135 cm².

  3. 3. Perimeter 40 cm, area 91 cm²

    Perimeter = 13 + 7 + 13 + 7 = 40 cm. Area = 13 × 7 = 91 cm².

  4. 4. Perimeter 52 cm, area 165 cm²

    Perimeter = 15 + 11 + 15 + 11 = 52 cm. Area = 15 × 11 = 165 cm².

  5. 5. 33 cm²

    Area = ½ × base × height. ½ × 22 × 3 = 33 cm².

  6. 6. 72 cm²

    Area = ½ × base × height. ½ × 12 × 12 = 72 cm².

  7. 7. 78 cm²

    Area = ½ × base × height. ½ × 12 × 13 = 78 cm².

  8. 8. 154 cm²

    Area = ½ × base × height. ½ × 28 × 11 = 154 cm².

  9. 9. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

  10. 10. Area 201.1 cm², circumference 50.3 cm

    Area = πr² = π × 8² = 201.1 cm². Circumference = 2πr = 2 × π × 8 = 50.3 cm.

  11. 11. Area 452.4 cm², circumference 75.4 cm

    Area = πr² = π × 12² = 452.4 cm². Circumference = 2πr = 2 × π × 12 = 75.4 cm.

  12. 12. Area 113.1 cm², circumference 37.7 cm

    Area = πr² = π × 6² = 113.1 cm². Circumference = 2πr = 2 × π × 6 = 37.7 cm.

Worked examples

Easy example

A rectangle is 9 cm by 8 cm. Find its perimeter and area.

  1. Perimeter = 9 + 8 + 9 + 8 = 34 cm.
  2. Area = 9 × 8 = 72 cm².
  3. Answer: Perimeter 34 cm, area 72 cm²
Medium example

A triangle has base 6 cm and height 15 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 6 × 15 = 45 cm².
  3. Answer: 45 cm²
Hard example

Find the area and circumference of a circle with radius 3 cm (to 1 d.p.).

  1. Area = πr² = π × 3² = 28.3 cm².
  2. Circumference = 2πr = 2 × π × 3 = 18.8 cm.
  3. Answer: Area 28.3 cm², circumference 18.8 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

OCR OCR-501.1 — Mapped statement covering Compound Shapes.CAMBRIDGE CAM-321.2 — Mapped statement covering Compound Shapes.

Every free resource for Compound Shapes

One concept, one ecosystem — all of it free.

Goes deeper

The entities below this one, each with the same complete free resource set.

Sibling concepts

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Frequently asked

Is this Grade 3 Compound Shapes flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Area of Circles, Area of Triangles, 2D Shapes. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Compound Shapes?
Move on to Angles, 2D Shapes, 3D Shapes, Transformations, which build directly on this idea.

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