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Free Grade 3 Introduction to Introducing Plotting Points Essentials Lesson Plans

Free Grade 3 lesson plans for Introduction to Introducing Plotting Points Essentials: 12 real questions with a full answer key and worked solutions. A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Price

Free

Difficulty

Core

Estimated time

30 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain introduction to introducing plotting points essentials

    Explain introduction to introducing plotting points essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introduction to introducing plotting points essentials

    Calculate introduction to introducing plotting points essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introduction to introducing plotting points essentials

    Compare introduction to introducing plotting points essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify introduction to introducing plotting points essentials

    Justify introduction to introducing plotting points essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introduction to Introducing Plotting Points Essentials works

A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Key wordscoordinateaxisquadrantgradientmidpoint

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.Which quadrant is the point (2, -5) in?[1]
  2. 2.Which quadrant is the point (-3, -2) in?[1]
  3. 3.Which quadrant is the point (4, 4) in?[1]
  4. 4.Which quadrant is the point (-5, -6) in?[1]
  5. 5.Find the midpoint of (-1, -6) and (1, -8).[2]
  6. 6.Find the midpoint of (-5, 0) and (-3, -6).[2]
  7. 7.Find the midpoint of (-2, -6) and (0, -8).[2]
  8. 8.Find the midpoint of (1, 6) and (5, 0).[2]
  9. 9.Find the equation of the line through (3, -2) and (11, 6).[3]
  10. 10.Find the equation of the line through (-1, -3) and (3, -11).[3]
  11. 11.Find the equation of the line through (5, 4) and (7, 4).[3]
  12. 12.Find the equation of the line through (5, 6) and (15, -2).[3]
Show answers and working
  1. 1. Fourth quadrant

    x is positive, y is negative. Quadrants go anticlockwise from top-right.

  2. 2. Third quadrant

    x is negative, y is negative. Quadrants go anticlockwise from top-right.

  3. 3. First quadrant

    x is positive, y is positive. Quadrants go anticlockwise from top-right.

  4. 4. Third quadrant

    x is negative, y is negative. Quadrants go anticlockwise from top-right.

  5. 5. (0, -7)

    Average the x values: (-1 + 1) ÷ 2 = 0. Average the y values: (-6 + -8) ÷ 2 = -7.

  6. 6. (-4, -3)

    Average the x values: (-5 + -3) ÷ 2 = -4. Average the y values: (0 + -6) ÷ 2 = -3.

  7. 7. (-1, -7)

    Average the x values: (-2 + 0) ÷ 2 = -1. Average the y values: (-6 + -8) ÷ 2 = -7.

  8. 8. (3, 3)

    Average the x values: (1 + 5) ÷ 2 = 3. Average the y values: (6 + 0) ÷ 2 = 3.

  9. 9. y = 1x − 5

    Gradient m = (6 − -2) / (11 − 3) = 1. Substitute (3, -2): c = -2 − 1 × 3 = -5.

  10. 10. y = -2x − 5

    Gradient m = (-11 − -3) / (3 − -1) = -2. Substitute (-1, -3): c = -3 − -2 × (-1) = -5.

  11. 11. y = 0x + 4

    Gradient m = (4 − 4) / (7 − 5) = 0. Substitute (5, 4): c = 4 − 0 × 5 = 4.

  12. 12. y = -0.8x + 10

    Gradient m = (-2 − 6) / (15 − 5) = -0.8. Substitute (5, 6): c = 6 − -0.8 × 5 = 10.

Worked examples

Easy example

Which quadrant is the point (-6, 5) in?

  1. x is negative, y is positive.
  2. Quadrants go anticlockwise from top-right.
  3. Answer: Second quadrant
Medium example

Find the midpoint of (3, -3) and (7, 5).

  1. Average the x values: (3 + 7) ÷ 2 = 5.
  2. Average the y values: (-3 + 5) ÷ 2 = 1.
  3. Answer: (5, 1)
Hard example

Find the equation of the line through (3, 6) and (11, 0).

  1. Gradient m = (0 − 6) / (11 − 3) = -0.75.
  2. Substitute (3, 6): c = 6 − -0.75 × 3 = 8.25.
  3. Answer: y = -0.75x + 8.25

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Plots (y, x) instead of (x, y).

    Correction: Along the corridor, then up the stairs.

  • Calculates gradient as run over rise.

    Correction: Gradient = change in y ÷ change in x.

Teacher tips

  • · Play coordinate battleships.

Parent tips

  • · Find places on a map using grid references.

Real-life applications

  • · Maps, game boards, GPS.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

FBISE FBI-320.1 — Mapped statement covering Introduction to Introducing Plotting Points Essentials.COMMON-CORE COM-172.2 — Mapped statement covering Introduction to Introducing Plotting Points Essentials.

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