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Free Grade 3 Distance Between Points in Context Lessons

Free Grade 3 lessons for Distance Between Points in Context: 12 real questions with a full answer key and worked solutions. A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Price

Free

Difficulty

Stretch

Estimated time

25 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain distance between points in context

    Explain distance between points in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate distance between points in context

    Calculate distance between points in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare distance between points in context

    Compare distance between points in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify distance between points in context

    Justify distance between points in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Distance Between Points in Context works

A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Key wordscoordinateaxisquadrantgradientmidpoint

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.Which quadrant is the point (1, 4) in?[1]
  2. 2.Which quadrant is the point (3, -3) in?[1]
  3. 3.Which quadrant is the point (-3, 2) in?[1]
  4. 4.Which quadrant is the point (6, 1) in?[1]
  5. 5.Find the midpoint of (-6, 4) and (2, 8).[2]
  6. 6.Find the midpoint of (2, 0) and (12, -4).[2]
  7. 7.Find the midpoint of (6, -4) and (16, -2).[2]
  8. 8.Find the midpoint of (-2, 0) and (4, 4).[2]
  9. 9.Find the equation of the line through (-6, -1) and (2, -1).[3]
  10. 10.Find the equation of the line through (-1, 6) and (5, 0).[3]
  11. 11.Find the equation of the line through (-1, -6) and (1, 2).[3]
  12. 12.Find the equation of the line through (3, 6) and (5, 0).[3]
Show answers and working
  1. 1. First quadrant

    x is positive, y is positive. Quadrants go anticlockwise from top-right.

  2. 2. Fourth quadrant

    x is positive, y is negative. Quadrants go anticlockwise from top-right.

  3. 3. Second quadrant

    x is negative, y is positive. Quadrants go anticlockwise from top-right.

  4. 4. First quadrant

    x is positive, y is positive. Quadrants go anticlockwise from top-right.

  5. 5. (-2, 6)

    Average the x values: (-6 + 2) ÷ 2 = -2. Average the y values: (4 + 8) ÷ 2 = 6.

  6. 6. (7, -2)

    Average the x values: (2 + 12) ÷ 2 = 7. Average the y values: (0 + -4) ÷ 2 = -2.

  7. 7. (11, -3)

    Average the x values: (6 + 16) ÷ 2 = 11. Average the y values: (-4 + -2) ÷ 2 = -3.

  8. 8. (1, 2)

    Average the x values: (-2 + 4) ÷ 2 = 1. Average the y values: (0 + 4) ÷ 2 = 2.

  9. 9. y = 0x − 1

    Gradient m = (-1 − -1) / (2 − -6) = 0. Substitute (-6, -1): c = -1 − 0 × (-6) = -1.

  10. 10. y = -1x + 5

    Gradient m = (0 − 6) / (5 − -1) = -1. Substitute (-1, 6): c = 6 − -1 × (-1) = 5.

  11. 11. y = 4x − 2

    Gradient m = (2 − -6) / (1 − -1) = 4. Substitute (-1, -6): c = -6 − 4 × (-1) = -2.

  12. 12. y = -3x + 15

    Gradient m = (0 − 6) / (5 − 3) = -3. Substitute (3, 6): c = 6 − -3 × 3 = 15.

Worked examples

Easy example

Which quadrant is the point (1, -2) in?

  1. x is positive, y is negative.
  2. Quadrants go anticlockwise from top-right.
  3. Answer: Fourth quadrant
Medium example

Find the midpoint of (-5, 5) and (5, 13).

  1. Average the x values: (-5 + 5) ÷ 2 = 0.
  2. Average the y values: (5 + 13) ÷ 2 = 9.
  3. Answer: (0, 9)
Hard example

Find the equation of the line through (6, -1) and (14, 1).

  1. Gradient m = (1 − -1) / (14 − 6) = 0.25.
  2. Substitute (6, -1): c = -1 − 0.25 × 6 = -2.5.
  3. Answer: y = 0.25x − 2.5

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Plots (y, x) instead of (x, y).

    Correction: Along the corridor, then up the stairs.

  • Calculates gradient as run over rise.

    Correction: Gradient = change in y ÷ change in x.

Teacher tips

  • · Play coordinate battleships.

Parent tips

  • · Find places on a map using grid references.

Real-life applications

  • · Maps, game boards, GPS.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

FBISE FBI-756.1 — Mapped statement covering Distance Between Points in Context.COMMON-CORE COM-956.2 — Mapped statement covering Distance Between Points in Context.

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Frequently asked

Is this Grade 3 Distance Between Points in Context lesson really free?
Yes. Every lessons on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Working with Distance Between Points, Introducing Distance Between Points, Midpoints. Each one has its own free lesson, worksheet and quiz.
How is the lesson sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Distance Between Points in Context?
Move on to Plotting Points, Midpoints, which build directly on this idea.

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