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Free Grade 3 Elimination Method in Context Common Errors Quizzes

Free Grade 3 quizzes for Elimination Method in Context Common Errors: 12 real questions with a full answer key and worked solutions. Simultaneous equations share the same solution. Eliminate or substitute one letter to find the other, then substitute back.

Price

Free

Difficulty

Stretch

Estimated time

25 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • RememberIdentify elimination method in context common errors

    Identify elimination method in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • UnderstandExplain elimination method in context common errors

    Explain elimination method in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate elimination method in context common errors

    Calculate elimination method in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare elimination method in context common errors

    Compare elimination method in context common errors accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Elimination Method in Context Common Errors works

Simultaneous equations share the same solution. Eliminate or substitute one letter to find the other, then substitute back.

Key wordssimultaneouseliminatesubstitute

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.Solve: 2x + 3y = 38 and x − y = -1.[1]
  2. 2.Solve: 3x + 4y = 36 and x − y = -2.[1]
  3. 3.Solve: 2x + 4y = 22 and x − y = -10.[1]
  4. 4.Solve: 1x + 3y = 22 and x − y = -2.[1]
  5. 5.Solve: 1x + 4y = 19 and x − y = -6.[2]
  6. 6.Solve: 2x + 2y = 2 and x − y = 5.[2]
  7. 7.Solve: 1x + 2y = 2 and x − y = -7.[2]
  8. 8.Solve: 4x + 2y = 2 and x − y = -10.[2]
  9. 9.Solve: 4x + 2y = -12 and x − y = 0.[3]
  10. 10.Solve: 2x + 1y = 9 and x − y = 3.[3]
  11. 11.Solve: 1x + 2y = 0 and x − y = 6.[3]
  12. 12.Solve: 1x + 4y = 19 and x − y = -1.[3]
Show answers and working
  1. 1. x = 7, y = 8

    From the second equation, x = y + -1. Substitute: 2(y + -1) + 3y = 38 → 5y = 40. y = 8, then x = 7.

  2. 2. x = 4, y = 6

    From the second equation, x = y + -2. Substitute: 3(y + -2) + 4y = 36 → 7y = 42. y = 6, then x = 4.

  3. 3. x = -3, y = 7

    From the second equation, x = y + -10. Substitute: 2(y + -10) + 4y = 22 → 6y = 42. y = 7, then x = -3.

  4. 4. x = 4, y = 6

    From the second equation, x = y + -2. Substitute: 1(y + -2) + 3y = 22 → 4y = 24. y = 6, then x = 4.

  5. 5. x = -1, y = 5

    From the second equation, x = y + -6. Substitute: 1(y + -6) + 4y = 19 → 5y = 25. y = 5, then x = -1.

  6. 6. x = 3, y = -2

    From the second equation, x = y + 5. Substitute: 2(y + 5) + 2y = 2 → 4y = -8. y = -2, then x = 3.

  7. 7. x = -4, y = 3

    From the second equation, x = y + -7. Substitute: 1(y + -7) + 2y = 2 → 3y = 9. y = 3, then x = -4.

  8. 8. x = -3, y = 7

    From the second equation, x = y + -10. Substitute: 4(y + -10) + 2y = 2 → 6y = 42. y = 7, then x = -3.

  9. 9. x = -2, y = -2

    From the second equation, x = y + 0. Substitute: 4(y + 0) + 2y = -12 → 6y = -12. y = -2, then x = -2.

  10. 10. x = 4, y = 1

    From the second equation, x = y + 3. Substitute: 2(y + 3) + 1y = 9 → 3y = 3. y = 1, then x = 4.

  11. 11. x = 4, y = -2

    From the second equation, x = y + 6. Substitute: 1(y + 6) + 2y = 0 → 3y = -6. y = -2, then x = 4.

  12. 12. x = 3, y = 4

    From the second equation, x = y + -1. Substitute: 1(y + -1) + 4y = 19 → 5y = 20. y = 4, then x = 3.

Worked examples

Easy example

Solve: 1x + 3y = 15 and x − y = -9.

  1. From the second equation, x = y + -9.
  2. Substitute: 1(y + -9) + 3y = 15 → 4y = 24.
  3. y = 6, then x = -3.
  4. Answer: x = -3, y = 6
Medium example

Solve: 2x + 2y = 8 and x − y = 8.

  1. From the second equation, x = y + 8.
  2. Substitute: 2(y + 8) + 2y = 8 → 4y = -8.
  3. y = -2, then x = 6.
  4. Answer: x = 6, y = -2
Hard example

Solve: 4x + 1y = 15 and x − y = 0.

  1. From the second equation, x = y + 0.
  2. Substitute: 4(y + 0) + 1y = 15 → 5y = 15.
  3. y = 3, then x = 3.
  4. Answer: x = 3, y = 3

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Stops after finding one letter.

    Correction: Substitute back to find the second.

  • Subtracts equations with mismatched signs.

    Correction: Same signs subtract, different signs add.

Teacher tips

  • · Start with real-life pairs (2 coffees + 1 cake = …).

Parent tips

  • · Puzzle: 2 apples and 1 banana cost $1.50…

Real-life applications

  • · Working out two prices from two shopping bills.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

CBSE CBS-583.1 — Mapped statement covering Elimination Method in Context Common Errors.COLLEGE-BOARD COL-436.2 — Mapped statement covering Elimination Method in Context Common Errors.

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What should a learner already know before this?
Start with Elimination Method in Context Word Problems, Elimination Method in Context Techniques, Working with Elimination Method. Each one has its own free lesson, worksheet and quiz.
How is the quiz sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Elimination Method in Context Common Errors?
Move on to Introducing Elimination Method, Working with Elimination Method, which build directly on this idea.

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