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Free Grade 3 Introducing Circles Lessons

Free Grade 3 lessons for Introducing Circles: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Stretch

Estimated time

20 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain introducing circles

    Explain introducing circles accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introducing circles

    Calculate introducing circles accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introducing circles

    Compare introducing circles accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify introducing circles

    Justify introducing circles accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introducing Circles works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 15 cm by 14 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 14 cm by 9 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 4 cm by 15 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 5 cm by 3 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 12 cm and height 8 cm. Find its area.[2]
  6. 6.A triangle has base 16 cm and height 14 cm. Find its area.[2]
  7. 7.A triangle has base 14 cm and height 14 cm. Find its area.[2]
  8. 8.A triangle has base 20 cm and height 15 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 8 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 6 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 12 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 58 cm, area 210 cm²

    Perimeter = 15 + 14 + 15 + 14 = 58 cm. Area = 15 × 14 = 210 cm².

  2. 2. Perimeter 46 cm, area 126 cm²

    Perimeter = 14 + 9 + 14 + 9 = 46 cm. Area = 14 × 9 = 126 cm².

  3. 3. Perimeter 38 cm, area 60 cm²

    Perimeter = 4 + 15 + 4 + 15 = 38 cm. Area = 4 × 15 = 60 cm².

  4. 4. Perimeter 16 cm, area 15 cm²

    Perimeter = 5 + 3 + 5 + 3 = 16 cm. Area = 5 × 3 = 15 cm².

  5. 5. 48 cm²

    Area = ½ × base × height. ½ × 12 × 8 = 48 cm².

  6. 6. 112 cm²

    Area = ½ × base × height. ½ × 16 × 14 = 112 cm².

  7. 7. 98 cm²

    Area = ½ × base × height. ½ × 14 × 14 = 98 cm².

  8. 8. 150 cm²

    Area = ½ × base × height. ½ × 20 × 15 = 150 cm².

  9. 9. Area 201.1 cm², circumference 50.3 cm

    Area = πr² = π × 8² = 201.1 cm². Circumference = 2πr = 2 × π × 8 = 50.3 cm.

  10. 10. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

  11. 11. Area 113.1 cm², circumference 37.7 cm

    Area = πr² = π × 6² = 113.1 cm². Circumference = 2πr = 2 × π × 6 = 37.7 cm.

  12. 12. Area 452.4 cm², circumference 75.4 cm

    Area = πr² = π × 12² = 452.4 cm². Circumference = 2πr = 2 × π × 12 = 75.4 cm.

Worked examples

Easy example

A rectangle is 11 cm by 13 cm. Find its perimeter and area.

  1. Perimeter = 11 + 13 + 11 + 13 = 48 cm.
  2. Area = 11 × 13 = 143 cm².
  3. Answer: Perimeter 48 cm, area 143 cm²
Medium example

A triangle has base 30 cm and height 8 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 30 × 8 = 120 cm².
  3. Answer: 120 cm²
Hard example

Find the area and circumference of a circle with radius 10 cm (to 1 d.p.).

  1. Area = πr² = π × 10² = 314.2 cm².
  2. Circumference = 2πr = 2 × π × 10 = 62.8 cm.
  3. Answer: Area 314.2 cm², circumference 62.8 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

FBISE FBI-150.1 — Mapped statement covering Introducing Circles.COMMON-CORE COM-514.2 — Mapped statement covering Introducing Circles.

Every free resource for Introducing Circles

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Frequently asked

Is this Grade 3 Introducing Circles lesson really free?
Yes. Every lessons on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Quadrilaterals. Each one has its own free lesson, worksheet and quiz.
How is the lesson sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Introducing Circles?
Move on to Working with Circles, Circles in Context, Triangles, Quadrilaterals, which build directly on this idea.

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