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Free Grade 3 Introducing Compound Shapes Word Problems Worksheets

Free Grade 3 worksheets for Introducing Compound Shapes Word Problems: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Stretch

Estimated time

25 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain introducing compound shapes word problems

    Explain introducing compound shapes word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introducing compound shapes word problems

    Calculate introducing compound shapes word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introducing compound shapes word problems

    Compare introducing compound shapes word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify introducing compound shapes word problems

    Justify introducing compound shapes word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introducing Compound Shapes Word Problems works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 13 cm by 12 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 12 cm by 7 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 14 cm by 3 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 9 cm by 4 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 16 cm and height 2 cm. Find its area.[2]
  6. 6.A triangle has base 26 cm and height 7 cm. Find its area.[2]
  7. 7.A triangle has base 20 cm and height 6 cm. Find its area.[2]
  8. 8.A triangle has base 14 cm and height 6 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 10 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 6 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 8 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 50 cm, area 156 cm²

    Perimeter = 13 + 12 + 13 + 12 = 50 cm. Area = 13 × 12 = 156 cm².

  2. 2. Perimeter 38 cm, area 84 cm²

    Perimeter = 12 + 7 + 12 + 7 = 38 cm. Area = 12 × 7 = 84 cm².

  3. 3. Perimeter 34 cm, area 42 cm²

    Perimeter = 14 + 3 + 14 + 3 = 34 cm. Area = 14 × 3 = 42 cm².

  4. 4. Perimeter 26 cm, area 36 cm²

    Perimeter = 9 + 4 + 9 + 4 = 26 cm. Area = 9 × 4 = 36 cm².

  5. 5. 16 cm²

    Area = ½ × base × height. ½ × 16 × 2 = 16 cm².

  6. 6. 91 cm²

    Area = ½ × base × height. ½ × 26 × 7 = 91 cm².

  7. 7. 60 cm²

    Area = ½ × base × height. ½ × 20 × 6 = 60 cm².

  8. 8. 42 cm²

    Area = ½ × base × height. ½ × 14 × 6 = 42 cm².

  9. 9. Area 314.2 cm², circumference 62.8 cm

    Area = πr² = π × 10² = 314.2 cm². Circumference = 2πr = 2 × π × 10 = 62.8 cm.

  10. 10. Area 113.1 cm², circumference 37.7 cm

    Area = πr² = π × 6² = 113.1 cm². Circumference = 2πr = 2 × π × 6 = 37.7 cm.

  11. 11. Area 201.1 cm², circumference 50.3 cm

    Area = πr² = π × 8² = 201.1 cm². Circumference = 2πr = 2 × π × 8 = 50.3 cm.

  12. 12. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

Worked examples

Easy example

A rectangle is 14 cm by 5 cm. Find its perimeter and area.

  1. Perimeter = 14 + 5 + 14 + 5 = 38 cm.
  2. Area = 14 × 5 = 70 cm².
  3. Answer: Perimeter 38 cm, area 70 cm²
Medium example

A triangle has base 28 cm and height 8 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 28 × 8 = 112 cm².
  3. Answer: 112 cm²
Hard example

Find the area and circumference of a circle with radius 9 cm (to 1 d.p.).

  1. Area = πr² = π × 9² = 254.5 cm².
  2. Circumference = 2πr = 2 × π × 9 = 56.5 cm.
  3. Answer: Area 254.5 cm², circumference 56.5 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

OCR OCR-789.1 — Mapped statement covering Introducing Compound Shapes Word Problems.CAMBRIDGE CAM-231.2 — Mapped statement covering Introducing Compound Shapes Word Problems.

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Frequently asked

Is this Grade 3 Introducing Compound Shapes Word Problems worksheet really free?
Yes. Every worksheets on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Introducing Compound Shapes Techniques, Introducing Compound Shapes Essentials, Area of Circles. Each one has its own free lesson, worksheet and quiz.
How is the worksheet sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Introducing Compound Shapes Word Problems?
Move on to Introducing Compound Shapes Common Errors, Working with Compound Shapes, Compound Shapes in Context, which build directly on this idea.

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