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Free Grade 3 Introducing Elimination Method Essentials Lesson Plans

Free Grade 3 lesson plans for Introducing Elimination Method Essentials: 12 real questions with a full answer key and worked solutions. Simultaneous equations share the same solution. Eliminate or substitute one letter to find the other, then substitute back.

Price

Free

Difficulty

Higher

Estimated time

35 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • RememberIdentify introducing elimination method essentials

    Identify introducing elimination method essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • UnderstandExplain introducing elimination method essentials

    Explain introducing elimination method essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introducing elimination method essentials

    Calculate introducing elimination method essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introducing elimination method essentials

    Compare introducing elimination method essentials accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introducing Elimination Method Essentials works

Simultaneous equations share the same solution. Eliminate or substitute one letter to find the other, then substitute back.

Key wordssimultaneouseliminatesubstitute

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.Solve: 1x + 2y = 18 and x − y = 3.[1]
  2. 2.Solve: 4x + 2y = 14 and x − y = 8.[1]
  3. 3.Solve: 1x + 1y = 1 and x − y = -7.[1]
  4. 4.Solve: 2x + 2y = 6 and x − y = -1.[1]
  5. 5.Solve: 3x + 3y = -12 and x − y = 0.[2]
  6. 6.Solve: 4x + 2y = -16 and x − y = -4.[2]
  7. 7.Solve: 2x + 2y = 30 and x − y = -1.[2]
  8. 8.Solve: 2x + 2y = 18 and x − y = -1.[2]
  9. 9.Solve: 3x + 1y = 21 and x − y = 11.[3]
  10. 10.Solve: 3x + 1y = -9 and x − y = -3.[3]
  11. 11.Solve: 2x + 4y = 8 and x − y = 4.[3]
  12. 12.Solve: 1x + 1y = 0 and x − y = 6.[3]
Show answers and working
  1. 1. x = 8, y = 5

    From the second equation, x = y + 3. Substitute: 1(y + 3) + 2y = 18 → 3y = 15. y = 5, then x = 8.

  2. 2. x = 5, y = -3

    From the second equation, x = y + 8. Substitute: 4(y + 8) + 2y = 14 → 6y = -18. y = -3, then x = 5.

  3. 3. x = -3, y = 4

    From the second equation, x = y + -7. Substitute: 1(y + -7) + 1y = 1 → 2y = 8. y = 4, then x = -3.

  4. 4. x = 1, y = 2

    From the second equation, x = y + -1. Substitute: 2(y + -1) + 2y = 6 → 4y = 8. y = 2, then x = 1.

  5. 5. x = -2, y = -2

    From the second equation, x = y + 0. Substitute: 3(y + 0) + 3y = -12 → 6y = -12. y = -2, then x = -2.

  6. 6. x = -4, y = 0

    From the second equation, x = y + -4. Substitute: 4(y + -4) + 2y = -16 → 6y = 0. y = 0, then x = -4.

  7. 7. x = 7, y = 8

    From the second equation, x = y + -1. Substitute: 2(y + -1) + 2y = 30 → 4y = 32. y = 8, then x = 7.

  8. 8. x = 4, y = 5

    From the second equation, x = y + -1. Substitute: 2(y + -1) + 2y = 18 → 4y = 20. y = 5, then x = 4.

  9. 9. x = 8, y = -3

    From the second equation, x = y + 11. Substitute: 3(y + 11) + 1y = 21 → 4y = -12. y = -3, then x = 8.

  10. 10. x = -3, y = 0

    From the second equation, x = y + -3. Substitute: 3(y + -3) + 1y = -9 → 4y = 0. y = 0, then x = -3.

  11. 11. x = 4, y = 0

    From the second equation, x = y + 4. Substitute: 2(y + 4) + 4y = 8 → 6y = 0. y = 0, then x = 4.

  12. 12. x = 3, y = -3

    From the second equation, x = y + 6. Substitute: 1(y + 6) + 1y = 0 → 2y = -6. y = -3, then x = 3.

Worked examples

Easy example

Solve: 2x + 4y = 32 and x − y = 1.

  1. From the second equation, x = y + 1.
  2. Substitute: 2(y + 1) + 4y = 32 → 6y = 30.
  3. y = 5, then x = 6.
  4. Answer: x = 6, y = 5
Medium example

Solve: 2x + 1y = 5 and x − y = 1.

  1. From the second equation, x = y + 1.
  2. Substitute: 2(y + 1) + 1y = 5 → 3y = 3.
  3. y = 1, then x = 2.
  4. Answer: x = 2, y = 1
Hard example

Solve: 4x + 1y = -1 and x − y = -9.

  1. From the second equation, x = y + -9.
  2. Substitute: 4(y + -9) + 1y = -1 → 5y = 35.
  3. y = 7, then x = -2.
  4. Answer: x = -2, y = 7

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Stops after finding one letter.

    Correction: Substitute back to find the second.

  • Subtracts equations with mismatched signs.

    Correction: Same signs subtract, different signs add.

Teacher tips

  • · Start with real-life pairs (2 coffees + 1 cake = …).

Parent tips

  • · Puzzle: 2 apples and 1 banana cost $1.50…

Real-life applications

  • · Working out two prices from two shopping bills.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

COMMON-CORE COM-819.1 — Mapped statement covering Introducing Elimination Method Essentials.OCR OCR-182.2 — Mapped statement covering Introducing Elimination Method Essentials.

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What should a learner already know before this?
Start with Quadratics. Each one has its own free lesson, worksheet and quiz.
How is the lesson plan sequenced?
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What comes next after Introducing Elimination Method Essentials?
Move on to Introducing Elimination Method Techniques, Introducing Elimination Method Word Problems, Introducing Elimination Method Common Errors, Working with Elimination Method, which build directly on this idea.

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