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Free Grade 3 Introducing Quadrilaterals Flashcards

Free Grade 3 flashcards for Introducing Quadrilaterals: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Foundation

Estimated time

35 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain introducing quadrilaterals

    Explain introducing quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introducing quadrilaterals

    Calculate introducing quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introducing quadrilaterals

    Compare introducing quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify introducing quadrilaterals

    Justify introducing quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introducing Quadrilaterals works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 2 cm by 11 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 4 cm by 2 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 15 cm by 11 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 7 cm by 7 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 14 cm and height 8 cm. Find its area.[2]
  6. 6.A triangle has base 18 cm and height 14 cm. Find its area.[2]
  7. 7.A triangle has base 24 cm and height 13 cm. Find its area.[2]
  8. 8.A triangle has base 20 cm and height 6 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 12 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 3 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 7 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 2 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 26 cm, area 22 cm²

    Perimeter = 2 + 11 + 2 + 11 = 26 cm. Area = 2 × 11 = 22 cm².

  2. 2. Perimeter 12 cm, area 8 cm²

    Perimeter = 4 + 2 + 4 + 2 = 12 cm. Area = 4 × 2 = 8 cm².

  3. 3. Perimeter 52 cm, area 165 cm²

    Perimeter = 15 + 11 + 15 + 11 = 52 cm. Area = 15 × 11 = 165 cm².

  4. 4. Perimeter 28 cm, area 49 cm²

    Perimeter = 7 + 7 + 7 + 7 = 28 cm. Area = 7 × 7 = 49 cm².

  5. 5. 56 cm²

    Area = ½ × base × height. ½ × 14 × 8 = 56 cm².

  6. 6. 126 cm²

    Area = ½ × base × height. ½ × 18 × 14 = 126 cm².

  7. 7. 156 cm²

    Area = ½ × base × height. ½ × 24 × 13 = 156 cm².

  8. 8. 60 cm²

    Area = ½ × base × height. ½ × 20 × 6 = 60 cm².

  9. 9. Area 452.4 cm², circumference 75.4 cm

    Area = πr² = π × 12² = 452.4 cm². Circumference = 2πr = 2 × π × 12 = 75.4 cm.

  10. 10. Area 28.3 cm², circumference 18.8 cm

    Area = πr² = π × 3² = 28.3 cm². Circumference = 2πr = 2 × π × 3 = 18.8 cm.

  11. 11. Area 153.9 cm², circumference 44 cm

    Area = πr² = π × 7² = 153.9 cm². Circumference = 2πr = 2 × π × 7 = 44 cm.

  12. 12. Area 12.6 cm², circumference 12.6 cm

    Area = πr² = π × 2² = 12.6 cm². Circumference = 2πr = 2 × π × 2 = 12.6 cm.

Worked examples

Easy example

A rectangle is 9 cm by 3 cm. Find its perimeter and area.

  1. Perimeter = 9 + 3 + 9 + 3 = 24 cm.
  2. Area = 9 × 3 = 27 cm².
  3. Answer: Perimeter 24 cm, area 27 cm²
Medium example

A triangle has base 16 cm and height 2 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 16 × 2 = 16 cm².
  3. Answer: 16 cm²
Hard example

Find the area and circumference of a circle with radius 8 cm (to 1 d.p.).

  1. Area = πr² = π × 8² = 201.1 cm².
  2. Circumference = 2πr = 2 × π × 8 = 50.3 cm.
  3. Answer: Area 201.1 cm², circumference 50.3 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

NATIONAL-CURRICULUM NAT-873.1 — Mapped statement covering Introducing Quadrilaterals.IB IB-572.2 — Mapped statement covering Introducing Quadrilaterals.

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Frequently asked

Is this Grade 3 Introducing Quadrilaterals flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Triangles. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Introducing Quadrilaterals?
Move on to Working with Quadrilaterals, Quadrilaterals in Context, Triangles, Circles, which build directly on this idea.

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