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Free Grade 3 Introducing Symmetry Flashcards

Free Grade 3 flashcards for Introducing Symmetry: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Foundation

Estimated time

30 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain introducing symmetry

    Explain introducing symmetry accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introducing symmetry

    Calculate introducing symmetry accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introducing symmetry

    Compare introducing symmetry accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify introducing symmetry

    Justify introducing symmetry accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introducing Symmetry works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 10 cm by 9 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 2 cm by 5 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 7 cm by 7 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 13 cm by 2 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 6 cm and height 5 cm. Find its area.[2]
  6. 6.A triangle has base 20 cm and height 14 cm. Find its area.[2]
  7. 7.A triangle has base 12 cm and height 9 cm. Find its area.[2]
  8. 8.A triangle has base 14 cm and height 4 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 8 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 10 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 2 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 38 cm, area 90 cm²

    Perimeter = 10 + 9 + 10 + 9 = 38 cm. Area = 10 × 9 = 90 cm².

  2. 2. Perimeter 14 cm, area 10 cm²

    Perimeter = 2 + 5 + 2 + 5 = 14 cm. Area = 2 × 5 = 10 cm².

  3. 3. Perimeter 28 cm, area 49 cm²

    Perimeter = 7 + 7 + 7 + 7 = 28 cm. Area = 7 × 7 = 49 cm².

  4. 4. Perimeter 30 cm, area 26 cm²

    Perimeter = 13 + 2 + 13 + 2 = 30 cm. Area = 13 × 2 = 26 cm².

  5. 5. 15 cm²

    Area = ½ × base × height. ½ × 6 × 5 = 15 cm².

  6. 6. 140 cm²

    Area = ½ × base × height. ½ × 20 × 14 = 140 cm².

  7. 7. 54 cm²

    Area = ½ × base × height. ½ × 12 × 9 = 54 cm².

  8. 8. 28 cm²

    Area = ½ × base × height. ½ × 14 × 4 = 28 cm².

  9. 9. Area 201.1 cm², circumference 50.3 cm

    Area = πr² = π × 8² = 201.1 cm². Circumference = 2πr = 2 × π × 8 = 50.3 cm.

  10. 10. Area 314.2 cm², circumference 62.8 cm

    Area = πr² = π × 10² = 314.2 cm². Circumference = 2πr = 2 × π × 10 = 62.8 cm.

  11. 11. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

  12. 12. Area 12.6 cm², circumference 12.6 cm

    Area = πr² = π × 2² = 12.6 cm². Circumference = 2πr = 2 × π × 2 = 12.6 cm.

Worked examples

Easy example

A rectangle is 15 cm by 8 cm. Find its perimeter and area.

  1. Perimeter = 15 + 8 + 15 + 8 = 46 cm.
  2. Area = 15 × 8 = 120 cm².
  3. Answer: Perimeter 46 cm, area 120 cm²
Medium example

A triangle has base 28 cm and height 9 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 28 × 9 = 126 cm².
  3. Answer: 126 cm²
Hard example

Find the area and circumference of a circle with radius 7 cm (to 1 d.p.).

  1. Area = πr² = π × 7² = 153.9 cm².
  2. Circumference = 2πr = 2 × π × 7 = 44 cm.
  3. Answer: Area 153.9 cm², circumference 44 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

FBISE FBI-682.1 — Mapped statement covering Introducing Symmetry.COMMON-CORE COM-558.2 — Mapped statement covering Introducing Symmetry.

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Frequently asked

Is this Grade 3 Introducing Symmetry flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Polygons. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Introducing Symmetry?
Move on to Working with Symmetry, Symmetry in Context, Triangles, Quadrilaterals, which build directly on this idea.

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