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Free Grade 3 Plotting Points in Context Techniques Flashcards

Free Grade 3 flashcards for Plotting Points in Context Techniques: 12 real questions with a full answer key and worked solutions. A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Price

Free

Difficulty

Higher

Estimated time

15 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain plotting points in context techniques

    Explain plotting points in context techniques accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate plotting points in context techniques

    Calculate plotting points in context techniques accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare plotting points in context techniques

    Compare plotting points in context techniques accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify plotting points in context techniques

    Justify plotting points in context techniques accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Plotting Points in Context Techniques works

A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Key wordscoordinateaxisquadrantgradientmidpoint

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.Which quadrant is the point (-2, -6) in?[1]
  2. 2.Which quadrant is the point (6, -3) in?[1]
  3. 3.Which quadrant is the point (1, 1) in?[1]
  4. 4.Which quadrant is the point (5, 5) in?[1]
  5. 5.Find the midpoint of (-5, 5) and (1, 3).[2]
  6. 6.Find the midpoint of (6, 3) and (16, 7).[2]
  7. 7.Find the midpoint of (-4, 6) and (6, 4).[2]
  8. 8.Find the midpoint of (-1, 5) and (7, 9).[2]
  9. 9.Find the equation of the line through (-1, 1) and (3, 3).[3]
  10. 10.Find the equation of the line through (6, -4) and (8, -6).[3]
  11. 11.Find the equation of the line through (6, 1) and (12, -5).[3]
  12. 12.Find the equation of the line through (1, 3) and (7, 7).[3]
Show answers and working
  1. 1. Third quadrant

    x is negative, y is negative. Quadrants go anticlockwise from top-right.

  2. 2. Fourth quadrant

    x is positive, y is negative. Quadrants go anticlockwise from top-right.

  3. 3. First quadrant

    x is positive, y is positive. Quadrants go anticlockwise from top-right.

  4. 4. First quadrant

    x is positive, y is positive. Quadrants go anticlockwise from top-right.

  5. 5. (-2, 4)

    Average the x values: (-5 + 1) ÷ 2 = -2. Average the y values: (5 + 3) ÷ 2 = 4.

  6. 6. (11, 5)

    Average the x values: (6 + 16) ÷ 2 = 11. Average the y values: (3 + 7) ÷ 2 = 5.

  7. 7. (1, 5)

    Average the x values: (-4 + 6) ÷ 2 = 1. Average the y values: (6 + 4) ÷ 2 = 5.

  8. 8. (3, 7)

    Average the x values: (-1 + 7) ÷ 2 = 3. Average the y values: (5 + 9) ÷ 2 = 7.

  9. 9. y = 0.5x + 1.5

    Gradient m = (3 − 1) / (3 − -1) = 0.5. Substitute (-1, 1): c = 1 − 0.5 × (-1) = 1.5.

  10. 10. y = -1x + 2

    Gradient m = (-6 − -4) / (8 − 6) = -1. Substitute (6, -4): c = -4 − -1 × 6 = 2.

  11. 11. y = -1x + 7

    Gradient m = (-5 − 1) / (12 − 6) = -1. Substitute (6, 1): c = 1 − -1 × 6 = 7.

  12. 12. y = 0.67x + 2.33

    Gradient m = (7 − 3) / (7 − 1) = 0.67. Substitute (1, 3): c = 3 − 0.67 × 1 = 2.33.

Worked examples

Easy example

Which quadrant is the point (-4, 4) in?

  1. x is negative, y is positive.
  2. Quadrants go anticlockwise from top-right.
  3. Answer: Second quadrant
Medium example

Find the midpoint of (-5, -2) and (-3, -4).

  1. Average the x values: (-5 + -3) ÷ 2 = -4.
  2. Average the y values: (-2 + -4) ÷ 2 = -3.
  3. Answer: (-4, -3)
Hard example

Find the equation of the line through (3, -1) and (5, 3).

  1. Gradient m = (3 − -1) / (5 − 3) = 2.
  2. Substitute (3, -1): c = -1 − 2 × 3 = -7.
  3. Answer: y = 2x − 7

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Plots (y, x) instead of (x, y).

    Correction: Along the corridor, then up the stairs.

  • Calculates gradient as run over rise.

    Correction: Gradient = change in y ÷ change in x.

Teacher tips

  • · Play coordinate battleships.

Parent tips

  • · Find places on a map using grid references.

Real-life applications

  • · Maps, game boards, GPS.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

EDEXCEL EDE-995.1 — Mapped statement covering Plotting Points in Context Techniques.CBSE CBS-732.2 — Mapped statement covering Plotting Points in Context Techniques.

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Frequently asked

Is this Grade 3 Plotting Points in Context Techniques flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Plotting Points in Context Essentials, Working with Plotting Points. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Plotting Points in Context Techniques?
Move on to Plotting Points in Context Word Problems, Plotting Points in Context Common Errors, Introducing Plotting Points, Working with Plotting Points, which build directly on this idea.

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