Free Grade 3 Rules and Methods in Introducing Probability Scale Common Errors Flashcards
Free Grade 3 flashcards for Rules and Methods in Introducing Probability Scale Common Errors: 12 real questions with a full answer key and worked solutions. Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
Free
Stretch
25 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- RememberIdentify rules and methods in introducing probability scale common errors
Identify rules and methods in introducing probability scale common errors accurately in a familiar context.
Assessed by: Exit ticket of four short items
- UnderstandExplain rules and methods in introducing probability scale common errors
Explain rules and methods in introducing probability scale common errors accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate rules and methods in introducing probability scale common errors
Calculate rules and methods in introducing probability scale common errors accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare rules and methods in introducing probability scale common errors
Compare rules and methods in introducing probability scale common errors accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Rules and Methods in Introducing Probability Scale Common Errors works
Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.A bag has 6 red, 5 blue and 0 green counters. One is picked at random. Find P(red).[1]
- 2.A bag has 3 red, 3 blue and 2 green counters. One is picked at random. Find P(red).[1]
- 3.A bag has 1 red, 6 blue and 5 green counters. One is picked at random. Find P(red).[1]
- 4.A bag has 4 red, 4 blue and 2 green counters. One is picked at random. Find P(red).[1]
- 5.A bag has 3 red, 8 blue and 1 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 6.A bag has 8 red, 8 blue and 4 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 7.A bag has 3 red, 6 blue and 0 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 8.A bag has 8 red, 6 blue and 5 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 9.A bag has 6 red and 7 blue counters. Two are picked with replacement. Find P(both red).[3]
- 10.A bag has 3 red and 1 blue counters. Two are picked with replacement. Find P(both red).[3]
- 11.A bag has 2 red and 6 blue counters. Two are picked with replacement. Find P(both red).[3]
- 12.A bag has 5 red and 8 blue counters. Two are picked with replacement. Find P(both red).[3]
Show answers and working
1. P(red) = 6/11
Total counters = 11. P(red) = 6/11 = 6/11.
2. P(red) = 3/8
Total counters = 8. P(red) = 3/8 = 3/8.
3. P(red) = 1/12
Total counters = 12. P(red) = 1/12 = 1/12.
4. P(red) = 2/5
Total counters = 10. P(red) = 4/10 = 2/5.
5. P(red) = 1/4, P(not red) = 3/4
Total counters = 12. P(red) = 3/12 = 1/4. P(not red) = 1 − 1/4 = 3/4.
6. P(red) = 2/5, P(not red) = 3/5
Total counters = 20. P(red) = 8/20 = 2/5. P(not red) = 1 − 2/5 = 3/5.
7. P(red) = 1/3, P(not red) = 2/3
Total counters = 9. P(red) = 3/9 = 1/3. P(not red) = 1 − 1/3 = 2/3.
8. P(red) = 8/19, P(not red) = 11/19
Total counters = 19. P(red) = 8/19 = 8/19. P(not red) = 1 − 8/19 = 11/19.
9. 36/169
P(red) = 6/13 each time. Independent, so multiply: 6/13 × 6/13 = 36/169.
10. 9/16
P(red) = 3/4 each time. Independent, so multiply: 3/4 × 3/4 = 9/16.
11. 1/16
P(red) = 2/8 each time. Independent, so multiply: 2/8 × 2/8 = 1/16.
12. 25/169
P(red) = 5/13 each time. Independent, so multiply: 5/13 × 5/13 = 25/169.
Worked examples
A bag has 4 red, 5 blue and 4 green counters. One is picked at random. Find P(red).
- Total counters = 13.
- P(red) = 4/13 = 4/13.
- Answer: P(red) = 4/13
A bag has 5 red, 3 blue and 3 green counters. One is picked at random. Find P(red) and P(not red).
- Total counters = 11.
- P(red) = 5/11 = 5/11.
- P(not red) = 1 − 5/11 = 6/11.
- Answer: P(red) = 5/11, P(not red) = 6/11
A bag has 1 red and 8 blue counters. Two are picked with replacement. Find P(both red).
- P(red) = 1/9 each time.
- Independent, so multiply: 1/9 × 1/9 = 1/81.
- Answer: 1/81
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Writes probability as a ratio like 3:5.
Correction: Use a fraction, decimal or percentage.
Adds probabilities for 'and' events.
Correction: 'And' means multiply when events are independent.
Teacher tips
- · Run real experiments with dice and compare to theory.
Parent tips
- · Talk about the chance of rain from the forecast.
Real-life applications
- · Weather forecasts, games, insurance.
Assessment objectives
How mastery is evidenced, and which standards it maps to.
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