Free Grade 3 Probability Scale in Context Techniques Flashcards
Free Grade 3 flashcards for Probability Scale in Context Techniques: 12 real questions with a full answer key and worked solutions. Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
Free
Foundation
35 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- UnderstandExplain probability scale in context techniques
Explain probability scale in context techniques accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate probability scale in context techniques
Calculate probability scale in context techniques accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare probability scale in context techniques
Compare probability scale in context techniques accurately in a familiar context.
Assessed by: Exit ticket of four short items
- EvaluateJustify probability scale in context techniques
Justify probability scale in context techniques accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Probability Scale in Context Techniques works
Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.A bag has 6 red, 6 blue and 1 green counters. One is picked at random. Find P(red).[1]
- 2.A bag has 5 red, 5 blue and 4 green counters. One is picked at random. Find P(red).[1]
- 3.A bag has 1 red, 2 blue and 5 green counters. One is picked at random. Find P(red).[1]
- 4.A bag has 7 red, 6 blue and 4 green counters. One is picked at random. Find P(red).[1]
- 5.A bag has 3 red, 1 blue and 1 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 6.A bag has 7 red, 6 blue and 0 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 7.A bag has 8 red, 5 blue and 2 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 8.A bag has 4 red, 2 blue and 1 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 9.A bag has 8 red and 5 blue counters. Two are picked with replacement. Find P(both red).[3]
- 10.A bag has 2 red and 5 blue counters. Two are picked with replacement. Find P(both red).[3]
- 11.A bag has 7 red and 2 blue counters. Two are picked with replacement. Find P(both red).[3]
- 12.A bag has 7 red and 7 blue counters. Two are picked with replacement. Find P(both red).[3]
Show answers and working
1. P(red) = 6/13
Total counters = 13. P(red) = 6/13 = 6/13.
2. P(red) = 5/14
Total counters = 14. P(red) = 5/14 = 5/14.
3. P(red) = 1/8
Total counters = 8. P(red) = 1/8 = 1/8.
4. P(red) = 7/17
Total counters = 17. P(red) = 7/17 = 7/17.
5. P(red) = 3/5, P(not red) = 2/5
Total counters = 5. P(red) = 3/5 = 3/5. P(not red) = 1 − 3/5 = 2/5.
6. P(red) = 7/13, P(not red) = 6/13
Total counters = 13. P(red) = 7/13 = 7/13. P(not red) = 1 − 7/13 = 6/13.
7. P(red) = 8/15, P(not red) = 7/15
Total counters = 15. P(red) = 8/15 = 8/15. P(not red) = 1 − 8/15 = 7/15.
8. P(red) = 4/7, P(not red) = 3/7
Total counters = 7. P(red) = 4/7 = 4/7. P(not red) = 1 − 4/7 = 3/7.
9. 64/169
P(red) = 8/13 each time. Independent, so multiply: 8/13 × 8/13 = 64/169.
10. 4/49
P(red) = 2/7 each time. Independent, so multiply: 2/7 × 2/7 = 4/49.
11. 49/81
P(red) = 7/9 each time. Independent, so multiply: 7/9 × 7/9 = 49/81.
12. 1/4
P(red) = 7/14 each time. Independent, so multiply: 7/14 × 7/14 = 1/4.
Worked examples
A bag has 8 red, 6 blue and 1 green counters. One is picked at random. Find P(red).
- Total counters = 15.
- P(red) = 8/15 = 8/15.
- Answer: P(red) = 8/15
A bag has 5 red, 7 blue and 0 green counters. One is picked at random. Find P(red) and P(not red).
- Total counters = 12.
- P(red) = 5/12 = 5/12.
- P(not red) = 1 − 5/12 = 7/12.
- Answer: P(red) = 5/12, P(not red) = 7/12
A bag has 8 red and 7 blue counters. Two are picked with replacement. Find P(both red).
- P(red) = 8/15 each time.
- Independent, so multiply: 8/15 × 8/15 = 64/225.
- Answer: 64/225
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Writes probability as a ratio like 3:5.
Correction: Use a fraction, decimal or percentage.
Adds probabilities for 'and' events.
Correction: 'And' means multiply when events are independent.
Teacher tips
- · Run real experiments with dice and compare to theory.
Parent tips
- · Talk about the chance of rain from the forecast.
Real-life applications
- · Weather forecasts, games, insurance.
Assessment objectives
How mastery is evidenced, and which standards it maps to.
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Frequently asked
- Is this Grade 3 Probability Scale in Context Techniques flashcards really free?
- Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
- What should a learner already know before this?
- Start with Probability Scale in Context Essentials, Working with Probability Scale. Each one has its own free lesson, worksheet and quiz.
- How is the flashcards sequenced?
- Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
- What comes next after Probability Scale in Context Techniques?
- Move on to Probability Scale in Context Word Problems, Probability Scale in Context Common Errors, Introducing Probability Scale, Working with Probability Scale, which build directly on this idea.
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