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Free Grade 3 Quadrilaterals in Context Flashcards

Free Grade 3 flashcards for Quadrilaterals in Context: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Core

Estimated time

15 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • RememberIdentify quadrilaterals in context

    Identify quadrilaterals in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • UnderstandExplain quadrilaterals in context

    Explain quadrilaterals in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate quadrilaterals in context

    Calculate quadrilaterals in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare quadrilaterals in context

    Compare quadrilaterals in context accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Quadrilaterals in Context works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 13 cm by 10 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 10 cm by 15 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 10 cm by 2 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 10 cm by 7 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 22 cm and height 13 cm. Find its area.[2]
  6. 6.A triangle has base 24 cm and height 3 cm. Find its area.[2]
  7. 7.A triangle has base 22 cm and height 12 cm. Find its area.[2]
  8. 8.A triangle has base 10 cm and height 10 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 2 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 9 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 3 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 46 cm, area 130 cm²

    Perimeter = 13 + 10 + 13 + 10 = 46 cm. Area = 13 × 10 = 130 cm².

  2. 2. Perimeter 50 cm, area 150 cm²

    Perimeter = 10 + 15 + 10 + 15 = 50 cm. Area = 10 × 15 = 150 cm².

  3. 3. Perimeter 24 cm, area 20 cm²

    Perimeter = 10 + 2 + 10 + 2 = 24 cm. Area = 10 × 2 = 20 cm².

  4. 4. Perimeter 34 cm, area 70 cm²

    Perimeter = 10 + 7 + 10 + 7 = 34 cm. Area = 10 × 7 = 70 cm².

  5. 5. 143 cm²

    Area = ½ × base × height. ½ × 22 × 13 = 143 cm².

  6. 6. 36 cm²

    Area = ½ × base × height. ½ × 24 × 3 = 36 cm².

  7. 7. 132 cm²

    Area = ½ × base × height. ½ × 22 × 12 = 132 cm².

  8. 8. 50 cm²

    Area = ½ × base × height. ½ × 10 × 10 = 50 cm².

  9. 9. Area 12.6 cm², circumference 12.6 cm

    Area = πr² = π × 2² = 12.6 cm². Circumference = 2πr = 2 × π × 2 = 12.6 cm.

  10. 10. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

  11. 11. Area 254.5 cm², circumference 56.5 cm

    Area = πr² = π × 9² = 254.5 cm². Circumference = 2πr = 2 × π × 9 = 56.5 cm.

  12. 12. Area 28.3 cm², circumference 18.8 cm

    Area = πr² = π × 3² = 28.3 cm². Circumference = 2πr = 2 × π × 3 = 18.8 cm.

Worked examples

Easy example

A rectangle is 12 cm by 5 cm. Find its perimeter and area.

  1. Perimeter = 12 + 5 + 12 + 5 = 34 cm.
  2. Area = 12 × 5 = 60 cm².
  3. Answer: Perimeter 34 cm, area 60 cm²
Medium example

A triangle has base 6 cm and height 13 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 6 × 13 = 39 cm².
  3. Answer: 39 cm²
Hard example

Find the area and circumference of a circle with radius 10 cm (to 1 d.p.).

  1. Area = πr² = π × 10² = 314.2 cm².
  2. Circumference = 2πr = 2 × π × 10 = 62.8 cm.
  3. Answer: Area 314.2 cm², circumference 62.8 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

COMMON-CORE COM-377.1 — Mapped statement covering Quadrilaterals in Context.OCR OCR-220.2 — Mapped statement covering Quadrilaterals in Context.

Every free resource for Quadrilaterals in Context

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Frequently asked

Is this Grade 3 Quadrilaterals in Context flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Working with Quadrilaterals, Introducing Quadrilaterals, Triangles. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Quadrilaterals in Context?
Move on to Triangles, Circles, Polygons, Symmetry, which build directly on this idea.

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