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Free Grade 3 Working with Compound Shapes Flashcards

Free Grade 3 flashcards for Working with Compound Shapes: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Higher

Estimated time

15 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain working with compound shapes

    Explain working with compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate working with compound shapes

    Calculate working with compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare working with compound shapes

    Compare working with compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify working with compound shapes

    Justify working with compound shapes accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Working with Compound Shapes works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 15 cm by 5 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 6 cm by 12 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 3 cm by 4 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 8 cm by 12 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 4 cm and height 10 cm. Find its area.[2]
  6. 6.A triangle has base 14 cm and height 11 cm. Find its area.[2]
  7. 7.A triangle has base 12 cm and height 15 cm. Find its area.[2]
  8. 8.A triangle has base 12 cm and height 4 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 3 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 2 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 11 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 5 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 40 cm, area 75 cm²

    Perimeter = 15 + 5 + 15 + 5 = 40 cm. Area = 15 × 5 = 75 cm².

  2. 2. Perimeter 36 cm, area 72 cm²

    Perimeter = 6 + 12 + 6 + 12 = 36 cm. Area = 6 × 12 = 72 cm².

  3. 3. Perimeter 14 cm, area 12 cm²

    Perimeter = 3 + 4 + 3 + 4 = 14 cm. Area = 3 × 4 = 12 cm².

  4. 4. Perimeter 40 cm, area 96 cm²

    Perimeter = 8 + 12 + 8 + 12 = 40 cm. Area = 8 × 12 = 96 cm².

  5. 5. 20 cm²

    Area = ½ × base × height. ½ × 4 × 10 = 20 cm².

  6. 6. 77 cm²

    Area = ½ × base × height. ½ × 14 × 11 = 77 cm².

  7. 7. 90 cm²

    Area = ½ × base × height. ½ × 12 × 15 = 90 cm².

  8. 8. 24 cm²

    Area = ½ × base × height. ½ × 12 × 4 = 24 cm².

  9. 9. Area 28.3 cm², circumference 18.8 cm

    Area = πr² = π × 3² = 28.3 cm². Circumference = 2πr = 2 × π × 3 = 18.8 cm.

  10. 10. Area 12.6 cm², circumference 12.6 cm

    Area = πr² = π × 2² = 12.6 cm². Circumference = 2πr = 2 × π × 2 = 12.6 cm.

  11. 11. Area 380.1 cm², circumference 69.1 cm

    Area = πr² = π × 11² = 380.1 cm². Circumference = 2πr = 2 × π × 11 = 69.1 cm.

  12. 12. Area 78.5 cm², circumference 31.4 cm

    Area = πr² = π × 5² = 78.5 cm². Circumference = 2πr = 2 × π × 5 = 31.4 cm.

Worked examples

Easy example

A rectangle is 15 cm by 13 cm. Find its perimeter and area.

  1. Perimeter = 15 + 13 + 15 + 13 = 56 cm.
  2. Area = 15 × 13 = 195 cm².
  3. Answer: Perimeter 56 cm, area 195 cm²
Medium example

A triangle has base 8 cm and height 7 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 8 × 7 = 28 cm².
  3. Answer: 28 cm²
Hard example

Find the area and circumference of a circle with radius 12 cm (to 1 d.p.).

  1. Area = πr² = π × 12² = 452.4 cm².
  2. Circumference = 2πr = 2 × π × 12 = 75.4 cm.
  3. Answer: Area 452.4 cm², circumference 75.4 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

EDEXCEL EDE-505.1 — Mapped statement covering Working with Compound Shapes.CBSE CBS-412.2 — Mapped statement covering Working with Compound Shapes.

Every free resource for Working with Compound Shapes

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Frequently asked

Is this Grade 3 Working with Compound Shapes flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Introducing Compound Shapes, Area of Circles. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Working with Compound Shapes?
Move on to Compound Shapes in Context, Perimeter of Rectangles, Area of Rectangles, Area of Triangles, which build directly on this idea.

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