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Free Grade 3 Working with Quadrilaterals Flashcards

Free Grade 3 flashcards for Working with Quadrilaterals: 12 real questions with a full answer key and worked solutions. Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Price

Free

Difficulty

Foundation

Estimated time

30 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • UnderstandExplain working with quadrilaterals

    Explain working with quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate working with quadrilaterals

    Calculate working with quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare working with quadrilaterals

    Compare working with quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • EvaluateJustify working with quadrilaterals

    Justify working with quadrilaterals accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Working with Quadrilaterals works

Perimeter is the distance around a shape; area is the space inside. Rectangle area = length × width; triangle = ½ × base × height; circle = πr².

Key wordsperimeterareasquare unitsradiuscircumference

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.A rectangle is 15 cm by 13 cm. Find its perimeter and area.[1]
  2. 2.A rectangle is 14 cm by 14 cm. Find its perimeter and area.[1]
  3. 3.A rectangle is 12 cm by 2 cm. Find its perimeter and area.[1]
  4. 4.A rectangle is 8 cm by 7 cm. Find its perimeter and area.[1]
  5. 5.A triangle has base 14 cm and height 9 cm. Find its area.[2]
  6. 6.A triangle has base 24 cm and height 3 cm. Find its area.[2]
  7. 7.A triangle has base 10 cm and height 5 cm. Find its area.[2]
  8. 8.A triangle has base 10 cm and height 14 cm. Find its area.[2]
  9. 9.Find the area and circumference of a circle with radius 3 cm (to 1 d.p.).[3]
  10. 10.Find the area and circumference of a circle with radius 10 cm (to 1 d.p.).[3]
  11. 11.Find the area and circumference of a circle with radius 8 cm (to 1 d.p.).[3]
  12. 12.Find the area and circumference of a circle with radius 11 cm (to 1 d.p.).[3]
Show answers and working
  1. 1. Perimeter 56 cm, area 195 cm²

    Perimeter = 15 + 13 + 15 + 13 = 56 cm. Area = 15 × 13 = 195 cm².

  2. 2. Perimeter 56 cm, area 196 cm²

    Perimeter = 14 + 14 + 14 + 14 = 56 cm. Area = 14 × 14 = 196 cm².

  3. 3. Perimeter 28 cm, area 24 cm²

    Perimeter = 12 + 2 + 12 + 2 = 28 cm. Area = 12 × 2 = 24 cm².

  4. 4. Perimeter 30 cm, area 56 cm²

    Perimeter = 8 + 7 + 8 + 7 = 30 cm. Area = 8 × 7 = 56 cm².

  5. 5. 63 cm²

    Area = ½ × base × height. ½ × 14 × 9 = 63 cm².

  6. 6. 36 cm²

    Area = ½ × base × height. ½ × 24 × 3 = 36 cm².

  7. 7. 25 cm²

    Area = ½ × base × height. ½ × 10 × 5 = 25 cm².

  8. 8. 70 cm²

    Area = ½ × base × height. ½ × 10 × 14 = 70 cm².

  9. 9. Area 28.3 cm², circumference 18.8 cm

    Area = πr² = π × 3² = 28.3 cm². Circumference = 2πr = 2 × π × 3 = 18.8 cm.

  10. 10. Area 314.2 cm², circumference 62.8 cm

    Area = πr² = π × 10² = 314.2 cm². Circumference = 2πr = 2 × π × 10 = 62.8 cm.

  11. 11. Area 201.1 cm², circumference 50.3 cm

    Area = πr² = π × 8² = 201.1 cm². Circumference = 2πr = 2 × π × 8 = 50.3 cm.

  12. 12. Area 380.1 cm², circumference 69.1 cm

    Area = πr² = π × 11² = 380.1 cm². Circumference = 2πr = 2 × π × 11 = 69.1 cm.

Worked examples

Easy example

A rectangle is 6 cm by 5 cm. Find its perimeter and area.

  1. Perimeter = 6 + 5 + 6 + 5 = 22 cm.
  2. Area = 6 × 5 = 30 cm².
  3. Answer: Perimeter 22 cm, area 30 cm²
Medium example

A triangle has base 12 cm and height 3 cm. Find its area.

  1. Area = ½ × base × height.
  2. ½ × 12 × 3 = 18 cm².
  3. Answer: 18 cm²
Hard example

Find the area and circumference of a circle with radius 9 cm (to 1 d.p.).

  1. Area = πr² = π × 9² = 254.5 cm².
  2. Circumference = 2πr = 2 × π × 9 = 56.5 cm.
  3. Answer: Area 254.5 cm², circumference 56.5 cm

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Mixes up area and perimeter.

    Correction: Perimeter is a fence (around), area is grass (inside).

  • Uses the slanted side as the height of a triangle.

    Correction: Height must be at right angles to the base.

Teacher tips

  • · Draw shapes on squared paper and count squares first.

Parent tips

  • · Measure a room and work out how much carpet you'd need.

Real-life applications

  • · Carpeting a room, fencing a garden.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

OCR OCR-367.1 — Mapped statement covering Working with Quadrilaterals.CAMBRIDGE CAM-959.2 — Mapped statement covering Working with Quadrilaterals.

Every free resource for Working with Quadrilaterals

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Frequently asked

Is this Grade 3 Working with Quadrilaterals flashcards really free?
Yes. Every flashcards on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Introducing Quadrilaterals, Triangles. Each one has its own free lesson, worksheet and quiz.
How is the flashcards sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Working with Quadrilaterals?
Move on to Quadrilaterals in Context, Triangles, Circles, Polygons, which build directly on this idea.

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