Free Grade 3 Rules and Methods in Introducing Plotting Points Essentials: Visual Models Quizzes
Free Grade 3 quizzes for Rules and Methods in Introducing Plotting Points Essentials: Visual Models: 12 real questions with a full answer key and worked solutions. A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.
Free
Foundation
20 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- UnderstandExplain rules and methods in introducing plotting points essentials: visual models
Explain rules and methods in introducing plotting points essentials: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate rules and methods in introducing plotting points essentials: visual models
Calculate rules and methods in introducing plotting points essentials: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare rules and methods in introducing plotting points essentials: visual models
Compare rules and methods in introducing plotting points essentials: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- EvaluateJustify rules and methods in introducing plotting points essentials: visual models
Justify rules and methods in introducing plotting points essentials: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Rules and Methods in Introducing Plotting Points Essentials: Visual Models works
A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.Which quadrant is the point (1, 6) in?[1]
- 2.Which quadrant is the point (6, -6) in?[1]
- 3.Which quadrant is the point (-4, 4) in?[1]
- 4.Which quadrant is the point (-4, -4) in?[1]
- 5.Find the midpoint of (2, -6) and (8, -12).[2]
- 6.Find the midpoint of (2, 0) and (6, -6).[2]
- 7.Find the midpoint of (6, 3) and (8, -1).[2]
- 8.Find the midpoint of (4, -2) and (12, 4).[2]
- 9.Find the equation of the line through (5, 6) and (11, 0).[3]
- 10.Find the equation of the line through (1, 3) and (3, -5).[3]
- 11.Find the equation of the line through (-5, -1) and (1, -1).[3]
- 12.Find the equation of the line through (4, -4) and (10, -12).[3]
Show answers and working
1. First quadrant
x is positive, y is positive. Quadrants go anticlockwise from top-right.
2. Fourth quadrant
x is positive, y is negative. Quadrants go anticlockwise from top-right.
3. Second quadrant
x is negative, y is positive. Quadrants go anticlockwise from top-right.
4. Third quadrant
x is negative, y is negative. Quadrants go anticlockwise from top-right.
5. (5, -9)
Average the x values: (2 + 8) ÷ 2 = 5. Average the y values: (-6 + -12) ÷ 2 = -9.
6. (4, -3)
Average the x values: (2 + 6) ÷ 2 = 4. Average the y values: (0 + -6) ÷ 2 = -3.
7. (7, 1)
Average the x values: (6 + 8) ÷ 2 = 7. Average the y values: (3 + -1) ÷ 2 = 1.
8. (8, 1)
Average the x values: (4 + 12) ÷ 2 = 8. Average the y values: (-2 + 4) ÷ 2 = 1.
9. y = -1x + 11
Gradient m = (0 − 6) / (11 − 5) = -1. Substitute (5, 6): c = 6 − -1 × 5 = 11.
10. y = -4x + 7
Gradient m = (-5 − 3) / (3 − 1) = -4. Substitute (1, 3): c = 3 − -4 × 1 = 7.
11. y = 0x − 1
Gradient m = (-1 − -1) / (1 − -5) = 0. Substitute (-5, -1): c = -1 − 0 × (-5) = -1.
12. y = -1.33x + 1.33
Gradient m = (-12 − -4) / (10 − 4) = -1.33. Substitute (4, -4): c = -4 − -1.33 × 4 = 1.33.
Worked examples
Which quadrant is the point (2, 5) in?
- x is positive, y is positive.
- Quadrants go anticlockwise from top-right.
- Answer: First quadrant
Find the midpoint of (0, 5) and (6, 13).
- Average the x values: (0 + 6) ÷ 2 = 3.
- Average the y values: (5 + 13) ÷ 2 = 9.
- Answer: (3, 9)
Find the equation of the line through (5, 4) and (9, 12).
- Gradient m = (12 − 4) / (9 − 5) = 2.
- Substitute (5, 4): c = 4 − 2 × 5 = -6.
- Answer: y = 2x − 6
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Plots (y, x) instead of (x, y).
Correction: Along the corridor, then up the stairs.
Calculates gradient as run over rise.
Correction: Gradient = change in y ÷ change in x.
Teacher tips
- · Play coordinate battleships.
Parent tips
- · Find places on a map using grid references.
Real-life applications
- · Maps, game boards, GPS.
Assessment objectives
How mastery is evidenced, and which standards it maps to.
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