Free Grade 3 Introduction to Introducing Plotting Points Techniques: Visual Models Quizzes
Free Grade 3 quizzes for Introduction to Introducing Plotting Points Techniques: Visual Models: 12 real questions with a full answer key and worked solutions. A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.
Free
Higher
30 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- UnderstandExplain introduction to introducing plotting points techniques: visual models
Explain introduction to introducing plotting points techniques: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate introduction to introducing plotting points techniques: visual models
Calculate introduction to introducing plotting points techniques: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare introduction to introducing plotting points techniques: visual models
Compare introduction to introducing plotting points techniques: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- EvaluateJustify introduction to introducing plotting points techniques: visual models
Justify introduction to introducing plotting points techniques: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Introduction to Introducing Plotting Points Techniques: Visual Models works
A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.Which quadrant is the point (3, 5) in?[1]
- 2.Which quadrant is the point (-1, 2) in?[1]
- 3.Which quadrant is the point (1, -1) in?[1]
- 4.Which quadrant is the point (-1, 5) in?[1]
- 5.Find the midpoint of (-2, 3) and (0, -5).[2]
- 6.Find the midpoint of (-5, 1) and (-1, -7).[2]
- 7.Find the midpoint of (-5, 0) and (-1, 8).[2]
- 8.Find the midpoint of (-2, -6) and (6, -14).[2]
- 9.Find the equation of the line through (-3, -4) and (5, -10).[3]
- 10.Find the equation of the line through (-1, 5) and (5, 13).[3]
- 11.Find the equation of the line through (-6, 0) and (4, -4).[3]
- 12.Find the equation of the line through (5, 3) and (7, -5).[3]
Show answers and working
1. First quadrant
x is positive, y is positive. Quadrants go anticlockwise from top-right.
2. Second quadrant
x is negative, y is positive. Quadrants go anticlockwise from top-right.
3. Fourth quadrant
x is positive, y is negative. Quadrants go anticlockwise from top-right.
4. Second quadrant
x is negative, y is positive. Quadrants go anticlockwise from top-right.
5. (-1, -1)
Average the x values: (-2 + 0) ÷ 2 = -1. Average the y values: (3 + -5) ÷ 2 = -1.
6. (-3, -3)
Average the x values: (-5 + -1) ÷ 2 = -3. Average the y values: (1 + -7) ÷ 2 = -3.
7. (-3, 4)
Average the x values: (-5 + -1) ÷ 2 = -3. Average the y values: (0 + 8) ÷ 2 = 4.
8. (2, -10)
Average the x values: (-2 + 6) ÷ 2 = 2. Average the y values: (-6 + -14) ÷ 2 = -10.
9. y = -0.75x − 6.25
Gradient m = (-10 − -4) / (5 − -3) = -0.75. Substitute (-3, -4): c = -4 − -0.75 × (-3) = -6.25.
10. y = 1.33x + 6.33
Gradient m = (13 − 5) / (5 − -1) = 1.33. Substitute (-1, 5): c = 5 − 1.33 × (-1) = 6.33.
11. y = -0.4x − 2.4
Gradient m = (-4 − 0) / (4 − -6) = -0.4. Substitute (-6, 0): c = 0 − -0.4 × (-6) = -2.4.
12. y = -4x + 23
Gradient m = (-5 − 3) / (7 − 5) = -4. Substitute (5, 3): c = 3 − -4 × 5 = 23.
Worked examples
Which quadrant is the point (6, -1) in?
- x is positive, y is negative.
- Quadrants go anticlockwise from top-right.
- Answer: Fourth quadrant
Find the midpoint of (1, 6) and (11, 10).
- Average the x values: (1 + 11) ÷ 2 = 6.
- Average the y values: (6 + 10) ÷ 2 = 8.
- Answer: (6, 8)
Find the equation of the line through (0, -3) and (4, 5).
- Gradient m = (5 − -3) / (4 − 0) = 2.
- Substitute (0, -3): c = -3 − 2 × 0 = -3.
- Answer: y = 2x − 3
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Plots (y, x) instead of (x, y).
Correction: Along the corridor, then up the stairs.
Calculates gradient as run over rise.
Correction: Gradient = change in y ÷ change in x.
Teacher tips
- · Play coordinate battleships.
Parent tips
- · Find places on a map using grid references.
Real-life applications
- · Maps, game boards, GPS.
Assessment objectives
How mastery is evidenced, and which standards it maps to.
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Frequently asked
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- What should a learner already know before this?
- Start with Introduction to Introducing Plotting Points Techniques: Worked Examples, Introduction to Introducing Plotting Points Techniques: Step-by-step Method, Introducing Plotting Points Essentials. Each one has its own free lesson, worksheet and quiz.
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- Move on to Introduction to Introducing Plotting Points Techniques: Common Mistakes, Introduction to Introducing Plotting Points Techniques: Real-life Applications, Key Vocabulary of Introducing Plotting Points Techniques, Rules and Methods in Introducing Plotting Points Techniques, which build directly on this idea.
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