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Free Grade 3 Introducing Parallel and Perpendicular Lines Word Problems Lessons

Free Grade 3 lessons for Introducing Parallel and Perpendicular Lines Word Problems: 12 real questions with a full answer key and worked solutions. A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Price

Free

Difficulty

Foundation

Estimated time

30 min

Total marks

24

Learning objectives

Every objective is checkable, and each one maps to an activity and an assessment.

  • RememberIdentify introducing parallel and perpendicular lines word problems

    Identify introducing parallel and perpendicular lines word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • UnderstandExplain introducing parallel and perpendicular lines word problems

    Explain introducing parallel and perpendicular lines word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • ApplyCalculate introducing parallel and perpendicular lines word problems

    Calculate introducing parallel and perpendicular lines word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

  • AnalyseCompare introducing parallel and perpendicular lines word problems

    Compare introducing parallel and perpendicular lines word problems accurately in a familiar context.

    Assessed by: Exit ticket of four short items

Prerequisites

Close these gaps first — each has its own free lesson, worksheet and quiz.

How Introducing Parallel and Perpendicular Lines Word Problems works

A coordinate (x, y) gives a position: across first, then up. The gradient of a line is rise over run, and y = mx + c describes a straight line.

Key wordscoordinateaxisquadrantgradientmidpoint

12 practice questions

Easy to hard, 24 marks in total. Try them first, then open the answers.

  1. 1.Which quadrant is the point (3, -4) in?[1]
  2. 2.Which quadrant is the point (6, -5) in?[1]
  3. 3.Which quadrant is the point (2, -2) in?[1]
  4. 4.Which quadrant is the point (-2, -6) in?[1]
  5. 5.Find the midpoint of (-4, 5) and (0, 9).[2]
  6. 6.Find the midpoint of (-5, 2) and (-3, 4).[2]
  7. 7.Find the midpoint of (-3, -5) and (-1, -9).[2]
  8. 8.Find the midpoint of (-6, -4) and (0, -6).[2]
  9. 9.Find the equation of the line through (-4, -2) and (2, 0).[3]
  10. 10.Find the equation of the line through (1, -1) and (9, -5).[3]
  11. 11.Find the equation of the line through (-1, -5) and (9, -5).[3]
  12. 12.Find the equation of the line through (-6, 2) and (4, 8).[3]
Show answers and working
  1. 1. Fourth quadrant

    x is positive, y is negative. Quadrants go anticlockwise from top-right.

  2. 2. Fourth quadrant

    x is positive, y is negative. Quadrants go anticlockwise from top-right.

  3. 3. Fourth quadrant

    x is positive, y is negative. Quadrants go anticlockwise from top-right.

  4. 4. Third quadrant

    x is negative, y is negative. Quadrants go anticlockwise from top-right.

  5. 5. (-2, 7)

    Average the x values: (-4 + 0) ÷ 2 = -2. Average the y values: (5 + 9) ÷ 2 = 7.

  6. 6. (-4, 3)

    Average the x values: (-5 + -3) ÷ 2 = -4. Average the y values: (2 + 4) ÷ 2 = 3.

  7. 7. (-2, -7)

    Average the x values: (-3 + -1) ÷ 2 = -2. Average the y values: (-5 + -9) ÷ 2 = -7.

  8. 8. (-3, -5)

    Average the x values: (-6 + 0) ÷ 2 = -3. Average the y values: (-4 + -6) ÷ 2 = -5.

  9. 9. y = 0.33x − 0.67

    Gradient m = (0 − -2) / (2 − -4) = 0.33. Substitute (-4, -2): c = -2 − 0.33 × (-4) = -0.67.

  10. 10. y = -0.5x − 0.5

    Gradient m = (-5 − -1) / (9 − 1) = -0.5. Substitute (1, -1): c = -1 − -0.5 × 1 = -0.5.

  11. 11. y = 0x − 5

    Gradient m = (-5 − -5) / (9 − -1) = 0. Substitute (-1, -5): c = -5 − 0 × (-1) = -5.

  12. 12. y = 0.6x + 5.6

    Gradient m = (8 − 2) / (4 − -6) = 0.6. Substitute (-6, 2): c = 2 − 0.6 × (-6) = 5.6.

Worked examples

Easy example

Which quadrant is the point (6, 6) in?

  1. x is positive, y is positive.
  2. Quadrants go anticlockwise from top-right.
  3. Answer: First quadrant
Medium example

Find the midpoint of (3, 5) and (11, 3).

  1. Average the x values: (3 + 11) ÷ 2 = 7.
  2. Average the y values: (5 + 3) ÷ 2 = 4.
  3. Answer: (7, 4)
Hard example

Find the equation of the line through (-2, 2) and (8, 8).

  1. Gradient m = (8 − 2) / (8 − -2) = 0.6.
  2. Substitute (-2, 2): c = 2 − 0.6 × (-2) = 3.2.
  3. Answer: y = 0.6x + 3.2

Interactive practice

Free, no account required — answer on screen or print it.

Common mistakes

What learners typically get wrong, and how to fix it.

  • Plots (y, x) instead of (x, y).

    Correction: Along the corridor, then up the stairs.

  • Calculates gradient as run over rise.

    Correction: Gradient = change in y ÷ change in x.

Teacher tips

  • · Play coordinate battleships.

Parent tips

  • · Find places on a map using grid references.

Real-life applications

  • · Maps, game boards, GPS.

Assessment objectives

How mastery is evidenced, and which standards it maps to.

COMMON-CORE COM-853.1 — Mapped statement covering Introducing Parallel and Perpendicular Lines Word Problems.OCR OCR-460.2 — Mapped statement covering Introducing Parallel and Perpendicular Lines Word Problems.

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Frequently asked

Is this Grade 3 Introducing Parallel and Perpendicular Lines Word Problems lesson really free?
Yes. Every lessons on FreeMathWorksheet is free to use, print and share — no account, no paywall and no watermark.
What should a learner already know before this?
Start with Introducing Parallel and Perpendicular Lines Techniques, Introducing Parallel and Perpendicular Lines Essentials, y = mx + c. Each one has its own free lesson, worksheet and quiz.
How is the lesson sequenced?
Recognition first, then understanding, application, reasoning and finally mastery — the same ladder used across every free resource on the platform.
What comes next after Introducing Parallel and Perpendicular Lines Word Problems?
Move on to Introducing Parallel and Perpendicular Lines Common Errors, Working with Parallel and Perpendicular Lines, Parallel and Perpendicular Lines in Context, which build directly on this idea.

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