Free Grade 3 Introducing Relative Frequency Essentials Flashcards
Free Grade 3 flashcards for Introducing Relative Frequency Essentials: 12 real questions with a full answer key and worked solutions. Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
Free
Core
20 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- RememberIdentify introducing relative frequency essentials
Identify introducing relative frequency essentials accurately in a familiar context.
Assessed by: Exit ticket of four short items
- UnderstandExplain introducing relative frequency essentials
Explain introducing relative frequency essentials accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate introducing relative frequency essentials
Calculate introducing relative frequency essentials accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare introducing relative frequency essentials
Compare introducing relative frequency essentials accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Introducing Relative Frequency Essentials works
Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.A bag has 3 red, 7 blue and 5 green counters. One is picked at random. Find P(red).[1]
- 2.A bag has 2 red, 3 blue and 5 green counters. One is picked at random. Find P(red).[1]
- 3.A bag has 8 red, 2 blue and 3 green counters. One is picked at random. Find P(red).[1]
- 4.A bag has 2 red, 3 blue and 1 green counters. One is picked at random. Find P(red).[1]
- 5.A bag has 7 red, 7 blue and 5 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 6.A bag has 2 red, 5 blue and 0 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 7.A bag has 4 red, 8 blue and 3 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 8.A bag has 3 red, 8 blue and 5 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 9.A bag has 8 red and 8 blue counters. Two are picked with replacement. Find P(both red).[3]
- 10.A bag has 2 red and 6 blue counters. Two are picked with replacement. Find P(both red).[3]
- 11.A bag has 7 red and 8 blue counters. Two are picked with replacement. Find P(both red).[3]
- 12.A bag has 5 red and 1 blue counters. Two are picked with replacement. Find P(both red).[3]
Show answers and working
1. P(red) = 1/5
Total counters = 15. P(red) = 3/15 = 1/5.
2. P(red) = 1/5
Total counters = 10. P(red) = 2/10 = 1/5.
3. P(red) = 8/13
Total counters = 13. P(red) = 8/13 = 8/13.
4. P(red) = 1/3
Total counters = 6. P(red) = 2/6 = 1/3.
5. P(red) = 7/19, P(not red) = 12/19
Total counters = 19. P(red) = 7/19 = 7/19. P(not red) = 1 − 7/19 = 12/19.
6. P(red) = 2/7, P(not red) = 5/7
Total counters = 7. P(red) = 2/7 = 2/7. P(not red) = 1 − 2/7 = 5/7.
7. P(red) = 4/15, P(not red) = 11/15
Total counters = 15. P(red) = 4/15 = 4/15. P(not red) = 1 − 4/15 = 11/15.
8. P(red) = 3/16, P(not red) = 13/16
Total counters = 16. P(red) = 3/16 = 3/16. P(not red) = 1 − 3/16 = 13/16.
9. 1/4
P(red) = 8/16 each time. Independent, so multiply: 8/16 × 8/16 = 1/4.
10. 1/16
P(red) = 2/8 each time. Independent, so multiply: 2/8 × 2/8 = 1/16.
11. 49/225
P(red) = 7/15 each time. Independent, so multiply: 7/15 × 7/15 = 49/225.
12. 25/36
P(red) = 5/6 each time. Independent, so multiply: 5/6 × 5/6 = 25/36.
Worked examples
A bag has 8 red, 4 blue and 1 green counters. One is picked at random. Find P(red).
- Total counters = 13.
- P(red) = 8/13 = 8/13.
- Answer: P(red) = 8/13
A bag has 6 red, 3 blue and 1 green counters. One is picked at random. Find P(red) and P(not red).
- Total counters = 10.
- P(red) = 6/10 = 3/5.
- P(not red) = 1 − 3/5 = 2/5.
- Answer: P(red) = 3/5, P(not red) = 2/5
A bag has 7 red and 1 blue counters. Two are picked with replacement. Find P(both red).
- P(red) = 7/8 each time.
- Independent, so multiply: 7/8 × 7/8 = 49/64.
- Answer: 49/64
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Writes probability as a ratio like 3:5.
Correction: Use a fraction, decimal or percentage.
Adds probabilities for 'and' events.
Correction: 'And' means multiply when events are independent.
Teacher tips
- · Run real experiments with dice and compare to theory.
Parent tips
- · Talk about the chance of rain from the forecast.
Real-life applications
- · Weather forecasts, games, insurance.
Assessment objectives
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Frequently asked
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- Start with Equally Likely Outcomes. Each one has its own free lesson, worksheet and quiz.
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- What comes next after Introducing Relative Frequency Essentials?
- Move on to Introducing Relative Frequency Techniques, Introducing Relative Frequency Word Problems, Introducing Relative Frequency Common Errors, Working with Relative Frequency, which build directly on this idea.
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