Free Grade 3 Working with Introducing Probability Scale Common Errors: Visual Models Flashcards
Free Grade 3 flashcards for Working with Introducing Probability Scale Common Errors: Visual Models: 12 real questions with a full answer key and worked solutions. Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
Free
Foundation
35 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- UnderstandExplain working with introducing probability scale common errors: visual models
Explain working with introducing probability scale common errors: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate working with introducing probability scale common errors: visual models
Calculate working with introducing probability scale common errors: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare working with introducing probability scale common errors: visual models
Compare working with introducing probability scale common errors: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
- EvaluateJustify working with introducing probability scale common errors: visual models
Justify working with introducing probability scale common errors: visual models accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Working with Introducing Probability Scale Common Errors: Visual Models works
Probability measures how likely something is, from 0 (impossible) to 1 (certain). P(event) = favourable outcomes ÷ total outcomes. For independent events, multiply.
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.A bag has 7 red, 8 blue and 0 green counters. One is picked at random. Find P(red).[1]
- 2.A bag has 8 red, 7 blue and 5 green counters. One is picked at random. Find P(red).[1]
- 3.A bag has 4 red, 8 blue and 1 green counters. One is picked at random. Find P(red).[1]
- 4.A bag has 4 red, 1 blue and 2 green counters. One is picked at random. Find P(red).[1]
- 5.A bag has 6 red, 6 blue and 0 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 6.A bag has 3 red, 5 blue and 1 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 7.A bag has 2 red, 3 blue and 5 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 8.A bag has 8 red, 4 blue and 3 green counters. One is picked at random. Find P(red) and P(not red).[2]
- 9.A bag has 6 red and 8 blue counters. Two are picked with replacement. Find P(both red).[3]
- 10.A bag has 2 red and 5 blue counters. Two are picked with replacement. Find P(both red).[3]
- 11.A bag has 4 red and 7 blue counters. Two are picked with replacement. Find P(both red).[3]
- 12.A bag has 8 red and 3 blue counters. Two are picked with replacement. Find P(both red).[3]
Show answers and working
1. P(red) = 7/15
Total counters = 15. P(red) = 7/15 = 7/15.
2. P(red) = 2/5
Total counters = 20. P(red) = 8/20 = 2/5.
3. P(red) = 4/13
Total counters = 13. P(red) = 4/13 = 4/13.
4. P(red) = 4/7
Total counters = 7. P(red) = 4/7 = 4/7.
5. P(red) = 1/2, P(not red) = 1/2
Total counters = 12. P(red) = 6/12 = 1/2. P(not red) = 1 − 1/2 = 1/2.
6. P(red) = 1/3, P(not red) = 2/3
Total counters = 9. P(red) = 3/9 = 1/3. P(not red) = 1 − 1/3 = 2/3.
7. P(red) = 1/5, P(not red) = 4/5
Total counters = 10. P(red) = 2/10 = 1/5. P(not red) = 1 − 1/5 = 4/5.
8. P(red) = 8/15, P(not red) = 7/15
Total counters = 15. P(red) = 8/15 = 8/15. P(not red) = 1 − 8/15 = 7/15.
9. 9/49
P(red) = 6/14 each time. Independent, so multiply: 6/14 × 6/14 = 9/49.
10. 4/49
P(red) = 2/7 each time. Independent, so multiply: 2/7 × 2/7 = 4/49.
11. 16/121
P(red) = 4/11 each time. Independent, so multiply: 4/11 × 4/11 = 16/121.
12. 64/121
P(red) = 8/11 each time. Independent, so multiply: 8/11 × 8/11 = 64/121.
Worked examples
A bag has 7 red, 2 blue and 1 green counters. One is picked at random. Find P(red).
- Total counters = 10.
- P(red) = 7/10 = 7/10.
- Answer: P(red) = 7/10
A bag has 6 red, 5 blue and 2 green counters. One is picked at random. Find P(red) and P(not red).
- Total counters = 13.
- P(red) = 6/13 = 6/13.
- P(not red) = 1 − 6/13 = 7/13.
- Answer: P(red) = 6/13, P(not red) = 7/13
A bag has 5 red and 2 blue counters. Two are picked with replacement. Find P(both red).
- P(red) = 5/7 each time.
- Independent, so multiply: 5/7 × 5/7 = 25/49.
- Answer: 25/49
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Writes probability as a ratio like 3:5.
Correction: Use a fraction, decimal or percentage.
Adds probabilities for 'and' events.
Correction: 'And' means multiply when events are independent.
Teacher tips
- · Run real experiments with dice and compare to theory.
Parent tips
- · Talk about the chance of rain from the forecast.
Real-life applications
- · Weather forecasts, games, insurance.
Assessment objectives
How mastery is evidenced, and which standards it maps to.
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