Free Grade 3 Introducing Vector Notation Techniques in Examinations Flashcards
Free Grade 3 flashcards for Introducing Vector Notation Techniques in Examinations: 12 real questions with a full answer key and worked solutions. A vector has size and direction. Add vectors component by component; multiply by a number to scale. Magnitude = √(x² + y²).
Free
Core
35 min
24
Learning objectives
Every objective is checkable, and each one maps to an activity and an assessment.
- RememberIdentify introducing vector notation techniques in examinations
Identify introducing vector notation techniques in examinations accurately in a familiar context.
Assessed by: Exit ticket of four short items
- UnderstandExplain introducing vector notation techniques in examinations
Explain introducing vector notation techniques in examinations accurately in a familiar context.
Assessed by: Exit ticket of four short items
- ApplyCalculate introducing vector notation techniques in examinations
Calculate introducing vector notation techniques in examinations accurately in a familiar context.
Assessed by: Exit ticket of four short items
- AnalyseCompare introducing vector notation techniques in examinations
Compare introducing vector notation techniques in examinations accurately in a familiar context.
Assessed by: Exit ticket of four short items
Prerequisites
Close these gaps first — each has its own free lesson, worksheet and quiz.
How Introducing Vector Notation Techniques in Examinations works
A vector has size and direction. Add vectors component by component; multiply by a number to scale. Magnitude = √(x² + y²).
12 practice questions
Easy to hard, 24 marks in total. Try them first, then open the answers.
- 1.a = (-2, -5), b = (-4, 0). Find a + 2b.[1]
- 2.a = (6, 2), b = (2, -6). Find a + 2b.[1]
- 3.a = (0, -6), b = (4, 4). Find a + 2b.[1]
- 4.a = (-3, -3), b = (0, -6). Find a + 4b.[1]
- 5.a = (-2, -6), b = (4, 1). Find a + 2b.[2]
- 6.a = (5, 4), b = (-3, -3). Find a + 3b.[2]
- 7.a = (-6, -3), b = (2, -5). Find a + 4b.[2]
- 8.a = (6, 3), b = (1, 0). Find a + 2b.[2]
- 9.Find the magnitude of (1, 3) to 2 d.p.[3]
- 10.Find the magnitude of (2, 6) to 2 d.p.[3]
- 11.Find the magnitude of (0, -2) to 2 d.p.[3]
- 12.Find the magnitude of (-1, 4) to 2 d.p.[3]
Show answers and working
1. (-10, -5)
2b = (-8, 0). Add components: (-2 + -8, -5 + 0).
2. (10, -10)
2b = (4, -12). Add components: (6 + 4, 2 + -12).
3. (8, 2)
2b = (8, 8). Add components: (0 + 8, -6 + 8).
4. (-3, -27)
4b = (0, -24). Add components: (-3 + 0, -3 + -24).
5. (6, -4)
2b = (8, 2). Add components: (-2 + 8, -6 + 2).
6. (-4, -5)
3b = (-9, -9). Add components: (5 + -9, 4 + -9).
7. (2, -23)
4b = (8, -20). Add components: (-6 + 8, -3 + -20).
8. (8, 3)
2b = (2, 0). Add components: (6 + 2, 3 + 0).
9. 3.16
|v| = √(x² + y²) = √(1 + 9). = 3.16.
10. 6.32
|v| = √(x² + y²) = √(4 + 36). = 6.32.
11. 2
|v| = √(x² + y²) = √(0 + 4). = 2.
12. 4.12
|v| = √(x² + y²) = √(1 + 16). = 4.12.
Worked examples
a = (2, -6), b = (4, -3). Find a + 3b.
- 3b = (12, -9).
- Add components: (2 + 12, -6 + -9).
- Answer: (14, -15)
a = (0, 6), b = (-4, -6). Find a + 4b.
- 4b = (-16, -24).
- Add components: (0 + -16, 6 + -24).
- Answer: (-16, -18)
Find the magnitude of (6, -2) to 2 d.p.
- |v| = √(x² + y²) = √(36 + 4).
- = 6.32.
- Answer: 6.32
Interactive practice
Free, no account required — answer on screen or print it.
Common mistakes
What learners typically get wrong, and how to fix it.
Adds x of one vector to y of the other.
Correction: Add x with x, y with y.
Forgets that a negative component means the opposite direction.
Correction: Draw the vector to check.
Teacher tips
- · Draw vectors on squared paper end to end.
Parent tips
- · Give directions as '3 steps right, 2 steps up'.
Real-life applications
- · Navigation, forces in physics, game movement.
Assessment objectives
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- Start with Working with Introducing Vector Notation Techniques, Rules and Methods in Introducing Vector Notation Techniques, Introducing Vector Notation Essentials. Each one has its own free lesson, worksheet and quiz.
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